Base | Representation |
---|---|
bin | 11001000001000001001110… |
… | …101111100010111111110100 |
3 | 112102112220221211101010022010 |
4 | 121001001032233202333310 |
5 | 103410041411023410200 |
6 | 1025555013145004220 |
7 | 32113524661116246 |
oct | 3101011657427764 |
9 | 472486854333263 |
10 | 110021203341300 |
11 | 32068804048359 |
12 | 1040aa1a483670 |
13 | 4950c55070364 |
14 | 1d250a9d86096 |
15 | cabd85e29150 |
hex | 64104ebe2ff4 |
110021203341300 has 72 divisors (see below), whose sum is σ = 318457051603936. Its totient is φ = 29327094783360.
The previous prime is 110021203341281. The next prime is 110021203341307. The reversal of 110021203341300 is 3143302120011.
It is a super-3 number, since 3×1100212033413003 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (110021203341307) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 73588507 + ... + 75068706.
Almost surely, 2110021203341300 is an apocalyptic number.
110021203341300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
110021203341300 is an abundant number, since it is smaller than the sum of its proper divisors (208435848262636).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
110021203341300 is a wasteful number, since it uses less digits than its factorization.
110021203341300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 148659697 (or 148659690 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 110021203341300 its reverse (3143302120011), we get a palindrome (113164505461311).
The spelling of 110021203341300 in words is "one hundred ten trillion, twenty-one billion, two hundred three million, three hundred forty-one thousand, three hundred".
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