Base | Representation |
---|---|
bin | 11001000001001100100111… |
… | …100010000101000100010100 |
3 | 112102121002111221202010102012 |
4 | 121001030213202011010110 |
5 | 103410241431140320200 |
6 | 1030004354325203352 |
7 | 32114436660322430 |
oct | 3101144742050424 |
9 | 472532457663365 |
10 | 110033430401300 |
11 | 32072a0899451a |
12 | 10411271260558 |
13 | 4952153274bc3 |
14 | 1d25909bcb9c0 |
15 | cac34e59ba35 |
hex | 641327885114 |
110033430401300 has 72 divisors (see below), whose sum is σ = 272959846993344. Its totient is φ = 37715110755840.
The previous prime is 110033430401291. The next prime is 110033430401333. The reversal of 110033430401300 is 3104034330011.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 19675349 + ... + 24641148.
Almost surely, 2110033430401300 is an apocalyptic number.
110033430401300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
110033430401300 is an abundant number, since it is smaller than the sum of its proper divisors (162926416592044).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
110033430401300 is a wasteful number, since it uses less digits than its factorization.
110033430401300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 44320065 (or 44320058 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 110033430401300 its reverse (3104034330011), we get a palindrome (113137464731311).
The spelling of 110033430401300 in words is "one hundred ten trillion, thirty-three billion, four hundred thirty million, four hundred one thousand, three hundred".
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