Base | Representation |
---|---|
bin | 10000000010010100111… |
… | …111001010000101011000 |
3 | 10220100111001111221002112 |
4 | 100002110333022011120 |
5 | 121023404332241440 |
6 | 2202131300451452 |
7 | 142421602514510 |
oct | 20022477120530 |
9 | 3810431457075 |
10 | 1102011212120 |
11 | 3953a6666475 |
12 | 1596b13a9b88 |
13 | 7cbc4679b10 |
14 | 3b4a2640840 |
15 | 1d9ec32a965 |
hex | 10094fca158 |
1102011212120 has 128 divisors (see below), whose sum is σ = 3053667133440. Its totient is φ = 348546240000.
The previous prime is 1102011212119. The next prime is 1102011212123. The reversal of 1102011212120 is 212121102011.
It is a Harshad number since it is a multiple of its sum of digits (14).
It is a junction number, because it is equal to n+sod(n) for n = 1102011212095 and 1102011212104.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1102011212123) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5666495 + ... + 5857745.
It is an arithmetic number, because the mean of its divisors is an integer number (23856774480).
Almost surely, 21102011212120 is an apocalyptic number.
1102011212120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1102011212120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1526833566720).
1102011212120 is an abundant number, since it is smaller than the sum of its proper divisors (1951655921320).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1102011212120 is a wasteful number, since it uses less digits than its factorization.
1102011212120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 192865 (or 192861 counting only the distinct ones).
The product of its (nonzero) digits is 16, while the sum is 14.
Adding to 1102011212120 its reverse (212121102011), we get a palindrome (1314132314131).
It can be divided in two parts, 1102011 and 212120, that added together give a palindrome (1314131).
The spelling of 1102011212120 in words is "one trillion, one hundred two billion, eleven million, two hundred twelve thousand, one hundred twenty".
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