Base | Representation |
---|---|
bin | 10000000011100010011… |
… | …110101011001111001100 |
3 | 10220110211122220020211200 |
4 | 100003202132223033030 |
5 | 121034040144220022 |
6 | 2202504302345500 |
7 | 142466040324516 |
oct | 20034236531714 |
9 | 3813748806750 |
10 | 1103311320012 |
11 | 395a03527800 |
12 | 1599b488b290 |
13 | 80070b21c25 |
14 | 3b58718cbb6 |
15 | 1da7653cbac |
hex | 100e27ab3cc |
1103311320012 has 108 divisors (see below), whose sum is σ = 3082452264528. Its totient is φ = 332489361600.
The previous prime is 1103311319969. The next prime is 1103311320019. The reversal of 1103311320012 is 2100231133011.
1103311320012 is a `hidden beast` number, since 1 + 1 + 0 + 331 + 1 + 320 + 0 + 12 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is not an unprimeable number, because it can be changed into a prime (1103311320019) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 88753 + ... + 1488119.
Almost surely, 21103311320012 is an apocalyptic number.
1103311320012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1103311320012, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1541226132264).
1103311320012 is an abundant number, since it is smaller than the sum of its proper divisors (1979140944516).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1103311320012 is a wasteful number, since it uses less digits than its factorization.
1103311320012 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1399580 (or 1399564 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 18.
Adding to 1103311320012 its reverse (2100231133011), we get a palindrome (3203542453023).
The spelling of 1103311320012 in words is "one trillion, one hundred three billion, three hundred eleven million, three hundred twenty thousand, twelve".
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