Base | Representation |
---|---|
bin | 10100100111000001… |
… | …00001101101100011 |
3 | 1001120010012121110110 |
4 | 22103200201231203 |
5 | 140130031241120 |
6 | 5025535102403 |
7 | 541123333446 |
oct | 122340415543 |
9 | 31503177413 |
10 | 11064712035 |
11 | 4768817a13 |
12 | 2189671a03 |
13 | 10744642b0 |
14 | 76d71765d |
15 | 44b5c32e0 |
hex | 293821b63 |
11064712035 has 64 divisors (see below), whose sum is σ = 20496107520. Its totient is φ = 5050667520.
The previous prime is 11064712033. The next prime is 11064712037. The reversal of 11064712035 is 53021746011.
It is an interprime number because it is at equal distance from previous prime (11064712033) and next prime (11064712037).
Together with 9431395484 it forms a betrothed pair.
It is not a de Polignac number, because 11064712035 - 21 = 11064712033 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11064711993 and 11064712011.
It is not an unprimeable number, because it can be changed into a prime (11064712031) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 142365 + ... + 205905.
It is an arithmetic number, because the mean of its divisors is an integer number (320251680).
Almost surely, 211064712035 is an apocalyptic number.
11064712035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11064712035 is a deficient number, since it is larger than the sum of its proper divisors (9431395485).
11064712035 is a wasteful number, since it uses less digits than its factorization.
11064712035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 63628.
The product of its (nonzero) digits is 5040, while the sum is 30.
The spelling of 11064712035 in words is "eleven billion, sixty-four million, seven hundred twelve thousand, thirty-five".
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