Base | Representation |
---|---|
bin | 10100101011001111… |
… | …00111000100011100 |
3 | 1001122120211200202020 |
4 | 22111213213010130 |
5 | 140213112422140 |
6 | 5033242100140 |
7 | 542033330601 |
oct | 122547470434 |
9 | 31576750666 |
10 | 11100123420 |
11 | 4786804021 |
12 | 21994aa650 |
13 | 107b8b2389 |
14 | 7742d46a8 |
15 | 44e76a6d0 |
hex | 2959e711c |
11100123420 has 48 divisors (see below), whose sum is σ = 31227681408. Its totient is φ = 2946000960.
The previous prime is 11100123373. The next prime is 11100123421. The reversal of 11100123420 is 2432100111.
11100123420 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 11100123420.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11100123421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 425734 + ... + 451053.
It is an arithmetic number, because the mean of its divisors is an integer number (650576696).
Almost surely, 211100123420 is an apocalyptic number.
11100123420 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11100123420 is an abundant number, since it is smaller than the sum of its proper divisors (20127557988).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11100123420 is a wasteful number, since it uses less digits than its factorization.
11100123420 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 877010 (or 877008 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 11100123420 its reverse (2432100111), we get a palindrome (13532223531).
It can be divided in two parts, 111001 and 23420, that added together give a triangular number (134421 = T518).
The spelling of 11100123420 in words is "eleven billion, one hundred million, one hundred twenty-three thousand, four hundred twenty".
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