11113543404340 has 144 divisors (see below), whose sum is σ = 26107364054016. Its totient is φ = 3967996032000.

The previous prime is 11113543404323. The next prime is 11113543404343. The reversal of 11113543404340 is 4340434531111.

It is a junction number, because it is equal to n+sod(n) for n = 11113543404296 and 11113543404305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11113543404343) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 136487640 + ... + 136569040.

It is an arithmetic number, because the mean of its divisors is an integer number (181301139264).

Almost surely, 2^{11113543404340} is an apocalyptic number.

11113543404340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11113543404340, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (13053682027008).

11113543404340 is an abundant number, since it is smaller than the sum of its proper divisors (14993820649676).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11113543404340 is a wasteful number, since it uses less digits than its factorization.

11113543404340 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 82770 (or 82755 counting only the distinct ones).

The product of its (nonzero) digits is 34560, while the sum is 34.

Adding to 11113543404340 its reverse (4340434531111), we get a palindrome (15453977935451).

The spelling of 11113543404340 in words is "eleven trillion, one hundred thirteen billion, five hundred forty-three million, four hundred four thousand, three hundred forty".