Base | Representation |
---|---|
bin | 11001010010001100001101… |
… | …001110101011001000010100 |
3 | 112120201201210020022001012200 |
4 | 121102030031032223020110 |
5 | 104033410044333224340 |
6 | 1032301045121444500 |
7 | 32265010621036656 |
oct | 3122141516531024 |
9 | 476651706261180 |
10 | 111201220211220 |
11 | 32483199888007 |
12 | 1057b65b7a0730 |
13 | 4a082cb608c29 |
14 | 1d6624c53a6d6 |
15 | ccc8eb5cc330 |
hex | 65230d3ab214 |
111201220211220 has 72 divisors (see below), whose sum is σ = 339076390947840. Its totient is φ = 29498403956160.
The previous prime is 111201220211197. The next prime is 111201220211251. The reversal of 111201220211220 is 22112022102111.
111201220211220 is a `hidden beast` number, since 1 + 1 + 1 + 201 + 220 + 21 + 1 + 220 = 666.
It is a super-2 number, since 2×1112012202112202 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 111201220211193 and 111201220211202.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1617202680 + ... + 1617271439.
It is an arithmetic number, because the mean of its divisors is an integer number (4709394318720).
Almost surely, 2111201220211220 is an apocalyptic number.
111201220211220 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
111201220211220 is an abundant number, since it is smaller than the sum of its proper divisors (227875170736620).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
111201220211220 is a wasteful number, since it uses less digits than its factorization.
111201220211220 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3234474325 (or 3234474320 counting only the distinct ones).
The product of its (nonzero) digits is 64, while the sum is 18.
Adding to 111201220211220 its reverse (22112022102111), we get a palindrome (133313242313331).
The spelling of 111201220211220 in words is "one hundred eleven trillion, two hundred one billion, two hundred twenty million, two hundred eleven thousand, two hundred twenty".
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