1113011330000 has 50 divisors (see below), whose sum is σ = 2694711755274. Its totient is φ = 445204528000.

The previous prime is 1113011329999. The next prime is 1113011330003. The reversal of 1113011330000 is 331103111.

It is a happy number.

It can be written as a sum of positive squares in 5 ways, for example, as 454745225104 + 658266104896 = 674348^2 + 811336^2 .

It is a tau number, because it is divible by the number of its divisors (50).

It is a super-4 number, since 4×1113011330000⁴ (a number of 49 digits) contains 4444 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1113011330003) by changing a digit.

It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 55640567 + ... + 55660566.

Almost surely, 2^{1113011330000} is an apocalyptic number.

1113011330000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1113011330000 is an abundant number, since it is smaller than the sum of its proper divisors (1581700425274).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1113011330000 is an equidigital number, since it uses as much as digits as its factorization.

1113011330000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 111301161 (or 111301140 counting only the distinct ones).

The product of its (nonzero) digits is 27, while the sum is 14.

Adding to 1113011330000 its reverse (331103111), we get a palindrome (1113342433111).

The spelling of 1113011330000 in words is "one trillion, one hundred thirteen billion, eleven million, three hundred thirty thousand".