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111311030013040 = 245111329347966907
BaseRepresentation
bin11001010011110010011110…
…011001110100110001110000
3112121010020020001210221201201
4121103302132121310301300
5104042204442140404130
61032423325314540544
732305646042665534
oct3123623631646160
9477106201727651
10111311030013040
113251581962a440
12105989a6897754
134a1577b5a1120
141d6b6a836dbc4
15cd06c6b54bca
hex653c9e674c70

111311030013040 has 320 divisors, whose sum is σ = 315433545960960. Its totient is φ = 35970759659520.

The previous prime is 111311030013019. The next prime is 111311030013049. The reversal of 111311030013040 is 40310030113111.

It is a happy number.

It is a junction number, because it is equal to n+sod(n) for n = 111311030012999 and 111311030013017.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (111311030013049) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 114637267 + ... + 115604173.

It is an arithmetic number, because the mean of its divisors is an integer number (985729831128).

Almost surely, 2111311030013040 is an apocalyptic number.

111311030013040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 111311030013040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (157716772980480).

111311030013040 is an abundant number, since it is smaller than the sum of its proper divisors (204122515947920).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

111311030013040 is a wasteful number, since it uses less digits than its factorization.

111311030013040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 967320 (or 967314 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 111311030013040 its reverse (40310030113111), we get a palindrome (151621060126151).

The spelling of 111311030013040 in words is "one hundred eleven trillion, three hundred eleven billion, thirty million, thirteen thousand, forty".