Base | Representation |
---|---|
bin | 100001001011000… |
… | …1011101100010000 |
3 | 2212120111220122220 |
4 | 1002112023230100 |
5 | 4234424030222 |
6 | 302241501040 |
7 | 36404201325 |
oct | 10226135420 |
9 | 2776456586 |
10 | 1113111312 |
11 | 521360005 |
12 | 270941780 |
13 | 1497c1761 |
14 | a7b92b4c |
15 | 67ac5b5c |
hex | 4258bb10 |
1113111312 has 160 divisors (see below), whose sum is σ = 3208937472. Its totient is φ = 330688512.
The previous prime is 1113111283. The next prime is 1113111319. The reversal of 1113111312 is 2131113111.
It is a super-2 number, since 2×11131113122 = 2478033585804722688, which contains 22 as substring.
It is a nude number because it is divisible by every one of its digits.
It is a junction number, because it is equal to n+sod(n) for n = 1113111291 and 1113111300.
It is not an unprimeable number, because it can be changed into a prime (1113111319) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2383303 + ... + 2383769.
Almost surely, 21113111312 is an apocalyptic number.
1113111312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1113111312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1604468736).
1113111312 is an abundant number, since it is smaller than the sum of its proper divisors (2095826160).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1113111312 is a wasteful number, since it uses less digits than its factorization.
1113111312 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 645 (or 639 counting only the distinct ones).
The product of its digits is 18, while the sum is 15.
The square root of 1113111312 is about 33363.3228560945. The cubic root of 1113111312 is about 1036.3653050030.
Adding to 1113111312 its reverse (2131113111), we get a palindrome (3244224423).
The spelling of 1113111312 in words is "one billion, one hundred thirteen million, one hundred eleven thousand, three hundred twelve".
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