Base | Representation |
---|---|
bin | 1101010001010… |
… | …00010011001000 |
3 | 21202110100021012 |
4 | 12220220103020 |
5 | 211444022440 |
6 | 15013503052 |
7 | 2521103651 |
oct | 650502310 |
9 | 252410235 |
10 | 111314120 |
11 | 57919a45 |
12 | 31341a88 |
13 | 1a0a5558 |
14 | 10ad8528 |
15 | 9b8be65 |
hex | 6a284c8 |
111314120 has 64 divisors (see below), whose sum is σ = 257774400. Its totient is φ = 43244800.
The previous prime is 111314117. The next prime is 111314129. The reversal of 111314120 is 21413111.
It is a super-2 number, since 2×1113141202 = 24781666622748800, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 111314095 and 111314104.
It is not an unprimeable number, because it can be changed into a prime (111314129) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 238127 + ... + 238593.
It is an arithmetic number, because the mean of its divisors is an integer number (4027725).
Almost surely, 2111314120 is an apocalyptic number.
111314120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 111314120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (128887200).
111314120 is an abundant number, since it is smaller than the sum of its proper divisors (146460280).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
111314120 is a wasteful number, since it uses less digits than its factorization.
111314120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 638 (or 634 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 14.
The square root of 111314120 is about 10550.5506965276. The cubic root of 111314120 is about 481.0424681161.
Adding to 111314120 its reverse (21413111), we get a palindrome (132727231).
It can be divided in two parts, 11131 and 4120, that added together give a palindrome (15251).
The spelling of 111314120 in words is "one hundred eleven million, three hundred fourteen thousand, one hundred twenty".
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