Search a number
-
+
111433000334112 = 2532386920140049
BaseRepresentation
bin11001010101100100000100…
…011001101011001100100000
3112121112220001101111020121200
4121111210010121223030200
5104101204241041142422
61032555340314121200
732320524425422332
oct3125440431531440
9477486041436550
10111433000334112
11325625196aa986
12105b8566420200
134a24118a40a42
141d73559247452
15cd3964aa92ac
hex65590466b320

111433000334112 has 36 divisors (see below), whose sum is σ = 316887594700950. Its totient is φ = 37144333444608.

The previous prime is 111433000334099. The next prime is 111433000334153. The reversal of 111433000334112 is 211433000334111.

111433000334112 is a `hidden beast` number, since 1 + 1 + 1 + 4 + 3 + 300 + 0 + 3 + 341 + 12 = 666.

It can be written as a sum of positive squares in only one way, i.e., 111425673658896 + 7326675216 = 10555836^2 + 85596^2 .

It is a tau number, because it is divible by the number of its divisors (36).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 193460069737 + ... + 193460070312.

Almost surely, 2111433000334112 is an apocalyptic number.

111433000334112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

111433000334112 is an abundant number, since it is smaller than the sum of its proper divisors (205454594366838).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

111433000334112 is a wasteful number, since it uses less digits than its factorization.

111433000334112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 386920140065 (or 386920140054 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 27.

Adding to 111433000334112 its reverse (211433000334111), we get a palindrome (322866000668223).

Subtracting 111433000334112 from its reverse (211433000334111), we obtain a palindrome (99999999999999).

The spelling of 111433000334112 in words is "one hundred eleven trillion, four hundred thirty-three billion, three hundred thirty-four thousand, one hundred twelve".

Divisors: 1 2 3 4 6 8 9 12 16 18 24 32 36 48 72 96 144 288 386920140049 773840280098 1160760420147 1547680560196 2321520840294 3095361120392 3482281260441 4643041680588 6190722240784 6964562520882 9286083361176 12381444481568 13929125041764 18572166722352 27858250083528 37144333444704 55716500167056 111433000334112