Base | Representation |
---|---|
bin | 10100111000101101… |
… | …01010100111010000 |
3 | 1001221110110121122211 |
4 | 22130112222213100 |
5 | 140431024401000 |
6 | 5052400041504 |
7 | 544604651533 |
oct | 123426524720 |
9 | 31843417584 |
10 | 11213122000 |
11 | 4834573583 |
12 | 220b303294 |
13 | 1099127542 |
14 | 78530aa1a |
15 | 45963b7ba |
hex | 29c5aa9d0 |
11213122000 has 40 divisors (see below), whose sum is σ = 27113333832. Its totient is φ = 4485248000.
The previous prime is 11213121979. The next prime is 11213122007. The reversal of 11213122000 is 22131211.
It can be written as a sum of positive squares in 4 ways, for example, as 16096144 + 11197025856 = 4012^2 + 105816^2 .
It is a tau number, because it is divible by the number of its divisors (40).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11213122007) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2801281 + ... + 2805280.
Almost surely, 211213122000 is an apocalyptic number.
11213122000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11213122000 is an abundant number, since it is smaller than the sum of its proper divisors (15900211832).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11213122000 is an equidigital number, since it uses as much as digits as its factorization.
11213122000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5606584 (or 5606568 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 11213122000 its reverse (22131211), we get a palindrome (11235253211).
The spelling of 11213122000 in words is "eleven billion, two hundred thirteen million, one hundred twenty-two thousand".
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