Base | Representation |
---|---|
bin | 11001100010010110000100… |
… | …100001001000101100110000 |
3 | 112201122212011012201211200102 |
4 | 121202112010201020230300 |
5 | 104210102042203231000 |
6 | 1034511035355211532 |
7 | 32441140166651411 |
oct | 3142260441105460 |
9 | 481585135654612 |
10 | 112311323102000 |
11 | 32870a67a39410 |
12 | 1071a82aa46ba8 |
13 | 4a88bb24b7b89 |
14 | 1da3c7b6ab808 |
15 | ceb71deb23d5 |
hex | 662584848b30 |
112311323102000 has 160 divisors (see below), whose sum is σ = 296289965657088. Its totient is φ = 40835916000000.
The previous prime is 112311323101979. The next prime is 112311323102053. The reversal of 112311323102000 is 201323113211.
It is a happy number.
It is a super-2 number, since 2×1123113231020002 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 199721225 + ... + 200282775.
Almost surely, 2112311323102000 is an apocalyptic number.
112311323102000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 112311323102000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (148144982828544).
112311323102000 is an abundant number, since it is smaller than the sum of its proper divisors (183978642555088).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
112311323102000 is a wasteful number, since it uses less digits than its factorization.
112311323102000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 570676 (or 570660 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 112311323102000 its reverse (201323113211), we get a palindrome (112512646215211).
It can be divided in two parts, 11231 and 1323102000, that added together give a palindrome (1323113231).
The spelling of 112311323102000 in words is "one hundred twelve trillion, three hundred eleven billion, three hundred twenty-three million, one hundred two thousand".
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