Base | Representation |
---|---|
bin | 11001101100010111011111… |
… | …011100100111011101100100 |
3 | 112211002200212022111120200010 |
4 | 121230113133130213131210 |
5 | 104302343042103130200 |
6 | 1040155300413450220 |
7 | 32541661263000333 |
oct | 3154273734473544 |
9 | 484080768446603 |
10 | 113000043411300 |
11 | 3300705a667481 |
12 | 108101b9aa0970 |
13 | 4b08b20ac0806 |
14 | 1dc93348d7d1a |
15 | d0e5ccb7e150 |
hex | 66c5df727764 |
113000043411300 has 72 divisors (see below), whose sum is σ = 326951240441056. Its totient is φ = 30132934940160.
The previous prime is 113000043411293. The next prime is 113000043411347. The reversal of 113000043411300 is 3114340000311.
113000043411300 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 19851084 + ... + 24901116.
Almost surely, 2113000043411300 is an apocalyptic number.
113000043411300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
113000043411300 is an abundant number, since it is smaller than the sum of its proper divisors (213951197029756).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113000043411300 is a wasteful number, since it uses less digits than its factorization.
113000043411300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5124637 (or 5124630 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 113000043411300 its reverse (3114340000311), we get a palindrome (116114383411611).
The spelling of 113000043411300 in words is "one hundred thirteen trillion, forty-three million, four hundred eleven thousand, three hundred".
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