Search a number
-
+
113011120111103 is a prime number
BaseRepresentation
bin11001101100100001110011…
…101010110111110111111111
3112211010202110021021020020222
4121230201303222313313333
5104303033233222023403
61040204331501531555
732542532623252634
oct3154416352676777
9484122407236228
10113011120111103
1133010824121a35
121081238b573bbb
134b09b97891356
141dc9aa5a5218b
15d0ea2a31e338
hex66c873ab7dff

113011120111103 has 2 divisors, whose sum is σ = 113011120111104. Its totient is φ = 113011120111102.

The previous prime is 113011120111081. The next prime is 113011120111111. The reversal of 113011120111103 is 301111021110311.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 113011120111103 - 216 = 113011120045567 is a prime.

It is a super-2 number, since 2×1130111201111032 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113011120111003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56505560055551 + 56505560055552.

It is an arithmetic number, because the mean of its divisors is an integer number (56505560055552).

Almost surely, 2113011120111103 is an apocalyptic number.

113011120111103 is a deficient number, since it is larger than the sum of its proper divisors (1).

113011120111103 is an equidigital number, since it uses as much as digits as its factorization.

113011120111103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 17.

Adding to 113011120111103 its reverse (301111021110311), we get a palindrome (414122141221414).

The spelling of 113011120111103 in words is "one hundred thirteen trillion, eleven billion, one hundred twenty million, one hundred eleven thousand, one hundred three".