Base | Representation |
---|---|
bin | 1010010001110011111011… |
… | …0100110111010101010100 |
3 | 1111000101010222220000210220 |
4 | 2210130332310313111110 |
5 | 2440124134412020200 |
6 | 40011354252114340 |
7 | 2244323054361513 |
oct | 244347664672524 |
9 | 44011128800726 |
10 | 11301113001300 |
11 | 36678587405a1 |
12 | 1326293a659b0 |
13 | 63c8c8a062c5 |
14 | 2b0d9643c67a |
15 | 148e7b91b4a0 |
hex | a473ed37554 |
11301113001300 has 72 divisors (see below), whose sum is σ = 33752657524992. Its totient is φ = 2916416256000.
The previous prime is 11301113001251. The next prime is 11301113001313. The reversal of 11301113001300 is 310031110311.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 11301113001300.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 607577421 + ... + 607596020.
Almost surely, 211301113001300 is an apocalyptic number.
11301113001300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11301113001300 is an abundant number, since it is smaller than the sum of its proper divisors (22451544523692).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11301113001300 is a wasteful number, since it uses less digits than its factorization.
11301113001300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1215173489 (or 1215173482 counting only the distinct ones).
The product of its (nonzero) digits is 27, while the sum is 15.
Adding to 11301113001300 its reverse (310031110311), we get a palindrome (11611144111611).
The spelling of 11301113001300 in words is "eleven trillion, three hundred one billion, one hundred thirteen million, one thousand, three hundred".
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