Base | Representation |
---|---|
bin | 110100101000010110… |
… | …0111010110101111111 |
3 | 101210201202220111011020 |
4 | 1221100230322311333 |
5 | 3322432403233320 |
6 | 123531101155223 |
7 | 11110550342613 |
oct | 1512054726577 |
9 | 353652814136 |
10 | 113023102335 |
11 | 43a2965a6a0 |
12 | 19aa325bb13 |
13 | a87290c960 |
14 | 56828c1343 |
15 | 2e17701940 |
hex | 1a50b3ad7f |
113023102335 has 64 divisors (see below), whose sum is σ = 213123294720. Its totient is φ = 50423892480.
The previous prime is 113023102331. The next prime is 113023102343. The reversal of 113023102335 is 533201320311.
It is not a de Polignac number, because 113023102335 - 22 = 113023102331 is a prime.
It is a super-2 number, since 2×1130231023352 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113023102331) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 596856 + ... + 763074.
It is an arithmetic number, because the mean of its divisors is an integer number (3330051480).
Almost surely, 2113023102335 is an apocalyptic number.
113023102335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
113023102335 is a deficient number, since it is larger than the sum of its proper divisors (100100192385).
113023102335 is a wasteful number, since it uses less digits than its factorization.
113023102335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 166568.
The product of its (nonzero) digits is 1620, while the sum is 24.
Adding to 113023102335 its reverse (533201320311), we get a palindrome (646224422646).
The spelling of 113023102335 in words is "one hundred thirteen billion, twenty-three million, one hundred two thousand, three hundred thirty-five".
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