Base | Representation |
---|---|
bin | 1010010010011001010000… |
… | …1001001111111111100100 |
3 | 1111001100000101210221102210 |
4 | 2210212110021033333210 |
5 | 2440310200342440030 |
6 | 40020132520203420 |
7 | 2245126311361542 |
oct | 244462411177744 |
9 | 44040011727383 |
10 | 11311134343140 |
11 | 3671030501a95 |
12 | 1328210009570 |
13 | 640834c56888 |
14 | 2b1667358d92 |
15 | 1493665e2bb0 |
hex | a499424ffe4 |
11311134343140 has 48 divisors (see below), whose sum is σ = 31984752179520. Its totient is φ = 2986438108800.
The previous prime is 11311134343133. The next prime is 11311134343147. The reversal of 11311134343140 is 4134343111311.
11311134343140 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (11311134343133) and next prime (11311134343147).
It is a super-2 number, since 2×113111343431402 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a junction number, because it is equal to n+sod(n) for n = 11311134343098 and 11311134343107.
It is not an unprimeable number, because it can be changed into a prime (11311134343147) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 933255850 + ... + 933267969.
It is an arithmetic number, because the mean of its divisors is an integer number (666349003740).
Almost surely, 211311134343140 is an apocalyptic number.
11311134343140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11311134343140 is an abundant number, since it is smaller than the sum of its proper divisors (20673617836380).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11311134343140 is a wasteful number, since it uses less digits than its factorization.
11311134343140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1866523932 (or 1866523930 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 30.
Adding to 11311134343140 its reverse (4134343111311), we get a palindrome (15445477454451).
The spelling of 11311134343140 in words is "eleven trillion, three hundred eleven billion, one hundred thirty-four million, three hundred forty-three thousand, one hundred forty".
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