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11311134343140 = 22351011866523819
BaseRepresentation
bin1010010010011001010000…
…1001001111111111100100
31111001100000101210221102210
42210212110021033333210
52440310200342440030
640020132520203420
72245126311361542
oct244462411177744
944040011727383
1011311134343140
113671030501a95
121328210009570
13640834c56888
142b1667358d92
151493665e2bb0
hexa499424ffe4

11311134343140 has 48 divisors (see below), whose sum is σ = 31984752179520. Its totient is φ = 2986438108800.

The previous prime is 11311134343133. The next prime is 11311134343147. The reversal of 11311134343140 is 4134343111311.

11311134343140 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (11311134343133) and next prime (11311134343147).

It is a super-2 number, since 2×113111343431402 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 11311134343098 and 11311134343107.

It is not an unprimeable number, because it can be changed into a prime (11311134343147) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 933255850 + ... + 933267969.

It is an arithmetic number, because the mean of its divisors is an integer number (666349003740).

Almost surely, 211311134343140 is an apocalyptic number.

11311134343140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

11311134343140 is an abundant number, since it is smaller than the sum of its proper divisors (20673617836380).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11311134343140 is a wasteful number, since it uses less digits than its factorization.

11311134343140 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1866523932 (or 1866523930 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 30.

Adding to 11311134343140 its reverse (4134343111311), we get a palindrome (15445477454451).

The spelling of 11311134343140 in words is "eleven trillion, three hundred eleven billion, one hundred thirty-four million, three hundred forty-three thousand, one hundred forty".

Divisors: 1 2 3 4 5 6 10 12 15 20 30 60 101 202 303 404 505 606 1010 1212 1515 2020 3030 6060 1866523819 3733047638 5599571457 7466095276 9332619095 11199142914 18665238190 22398285828 27997857285 37330476380 55995714570 111991429140 188518905719 377037811438 565556717157 754075622876 942594528595 1131113434314 1885189057190 2262226868628 2827783585785 3770378114380 5655567171570 11311134343140