Base | Representation |
---|---|
bin | 1010010010011001111010… |
… | …1100010010110101101111 |
3 | 1111001100110201210101100121 |
4 | 2210212132230102311233 |
5 | 2440311031143130444 |
6 | 40020202241105411 |
7 | 2245133560452562 |
oct | 244463654226557 |
9 | 44040421711317 |
10 | 11311311301999 |
11 | 3671111387885 |
12 | 132825b328267 |
13 | 640862804467 |
14 | 2b1682a604d9 |
15 | 149376dea084 |
hex | a499eb12d6f |
11311311301999 has 4 divisors (see below), whose sum is σ = 11318529753664. Its totient is φ = 11304092850336.
The previous prime is 11311311301981. The next prime is 11311311302047. The reversal of 11311311301999 is 99910311311311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11311311301999 - 25 = 11311311301967 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11311311341999) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3609223482 + ... + 3609226615.
It is an arithmetic number, because the mean of its divisors is an integer number (2829632438416).
Almost surely, 211311311301999 is an apocalyptic number.
11311311301999 is a deficient number, since it is larger than the sum of its proper divisors (7218451665).
11311311301999 is an equidigital number, since it uses as much as digits as its factorization.
11311311301999 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7218451664.
The product of its (nonzero) digits is 19683, while the sum is 43.
The spelling of 11311311301999 in words is "eleven trillion, three hundred eleven billion, three hundred eleven million, three hundred one thousand, nine hundred ninety-nine".
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