Base | Representation |
---|---|
bin | 10101000100100000… |
… | …10111000011010110 |
3 | 1002012100202212021100 |
4 | 22202100113003112 |
5 | 141131401213220 |
6 | 5110254130530 |
7 | 550216352403 |
oct | 124220270326 |
9 | 32170685240 |
10 | 11312132310 |
11 | 4885449486 |
12 | 22384b0a46 |
13 | 10b37b271b |
14 | 7945212aa |
15 | 463197d90 |
hex | 2a24170d6 |
11312132310 has 48 divisors (see below), whose sum is σ = 29702771280. Its totient is φ = 2986699200.
The previous prime is 11312132291. The next prime is 11312132323. The reversal of 11312132310 is 1323121311.
11312132310 is a `hidden beast` number, since 11 + 312 + 1 + 32 + 310 = 666.
It is a super-2 number, since 2×113121323102 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 613140 + ... + 631319.
It is an arithmetic number, because the mean of its divisors is an integer number (618807735).
Almost surely, 211312132310 is an apocalyptic number.
11312132310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11312132310 is an abundant number, since it is smaller than the sum of its proper divisors (18390638970).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11312132310 is a wasteful number, since it uses less digits than its factorization.
11312132310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1244573 (or 1244570 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 18.
Adding to 11312132310 its reverse (1323121311), we get a palindrome (12635253621).
The spelling of 11312132310 in words is "eleven billion, three hundred twelve million, one hundred thirty-two thousand, three hundred ten".
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