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113122131320 = 235114313145641
BaseRepresentation
bin110100101011010011…
…0101011110101111000
3101210222200020200101102
41221112212223311320
53323133231200240
6123544555510532
711113162152062
oct1512646536570
9353880220342
10113122131320
1143a7a548630
1219b10458448
13a88a2a34a3
145691adc732
152e21263815
hex1a569abd78

113122131320 has 128 divisors (see below), whose sum is σ = 286295834880. Its totient is φ = 39871104000.

The previous prime is 113122131313. The next prime is 113122131359. The reversal of 113122131320 is 23131221311.

It is a happy number.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 113122131292 and 113122131301.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2455700 + ... + 2501340.

It is an arithmetic number, because the mean of its divisors is an integer number (2236686210).

Almost surely, 2113122131320 is an apocalyptic number.

113122131320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 113122131320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (143147917440).

113122131320 is an abundant number, since it is smaller than the sum of its proper divisors (173173703560).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113122131320 is a wasteful number, since it uses less digits than its factorization.

113122131320 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 45837 (or 45833 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 113122131320 its reverse (23131221311), we get a palindrome (136253352631).

It can be divided in two parts, 113122 and 131320, that added together give a palindrome (244442).

The spelling of 113122131320 in words is "one hundred thirteen billion, one hundred twenty-two million, one hundred thirty-one thousand, three hundred twenty".

Divisors: 1 2 4 5 8 10 11 20 22 40 43 44 55 86 88 110 131 172 215 220 262 344 430 440 473 524 655 860 946 1048 1310 1441 1720 1892 2365 2620 2882 3784 4730 5240 5633 5764 7205 9460 11266 11528 14410 18920 22532 28165 28820 45064 45641 56330 57640 61963 91282 112660 123926 182564 225320 228205 247852 309815 365128 456410 495704 502051 619630 912820 1004102 1239260 1825640 1962563 2008204 2478520 2510255 3925126 4016408 5020510 5978971 7850252 9812815 10041020 11957942 15700504 19625630 20082040 21588193 23915884 29894855 39251260 43176386 47831768 59789710 65768681 78502520 86352772 107940965 119579420 131537362 172705544 215881930 239158840 257095753 263074724 328843405 431763860 514191506 526149448 657686810 863527720 1028383012 1285478765 1315373620 2056766024 2570957530 2630747240 2828053283 5141915060 5656106566 10283830120 11312213132 14140266415 22624426264 28280532830 56561065660 113122131320