1131310000000 has 128 divisors (see below), whose sum is σ = 2817244740960. Its totient is φ = 452520000000.

The previous prime is 1131309999973. The next prime is 1131310000021. The reversal of 1131310000000 is 131311.

It is a tau number, because it is divible by the number of its divisors (128).

It is a super-2 number, since 2×1131310000000² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (10).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9943435 + ... + 10056565.

Almost surely, 2^{1131310000000} is an apocalyptic number.

1131310000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1131310000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1408622370480).

1131310000000 is an abundant number, since it is smaller than the sum of its proper divisors (1685934740960).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1131310000000 is an frugal number, since it uses more digits than its factorization.

1131310000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 113180 (or 113138 counting only the distinct ones).

The product of its (nonzero) digits is 9, while the sum is 10.

Adding to 1131310000000 its reverse (131311), we get a palindrome (1131310131311).

The spelling of 1131310000000 in words is "one trillion, one hundred thirty-one billion, three hundred ten million", and thus it is an aban number.