Base | Representation |
---|---|
bin | 10000011101100111011… |
… | …001010111100100011000 |
3 | 11000011010000102120020210 |
4 | 100131213121113210120 |
5 | 122013411120232412 |
6 | 2223414523051120 |
7 | 144506641463613 |
oct | 20354731274430 |
9 | 4004100376223 |
10 | 1131311102232 |
11 | 3a6871695593 |
12 | 163309970aa0 |
13 | 828b39947bc |
14 | 3ca81ac317a |
15 | 1e66475e83c |
hex | 10767657918 |
1131311102232 has 96 divisors (see below), whose sum is σ = 3085635067920. Its totient is φ = 345328588800.
The previous prime is 1131311102197. The next prime is 1131311102237. The reversal of 1131311102232 is 2322011131311.
It is a junction number, because it is equal to n+sod(n) for n = 1131311102199 and 1131311102208.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1131311102237) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1947519 + ... + 2460782.
Almost surely, 21131311102232 is an apocalyptic number.
1131311102232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1131311102232 is an abundant number, since it is smaller than the sum of its proper divisors (1954323965688).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1131311102232 is a wasteful number, since it uses less digits than its factorization.
1131311102232 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4408381 (or 4408360 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 1131311102232 its reverse (2322011131311), we get a palindrome (3453322233543).
The spelling of 1131311102232 in words is "one trillion, one hundred thirty-one billion, three hundred eleven million, one hundred two thousand, two hundred thirty-two".
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