Base | Representation |
---|---|
bin | 10101000100101000… |
… | …11110111011001100 |
3 | 1002012102210202212210 |
4 | 22202110132323030 |
5 | 141132140310012 |
6 | 5110333230420 |
7 | 550231503444 |
oct | 124224367314 |
9 | 32172722783 |
10 | 11313213132 |
11 | 4886017521 |
12 | 2238932410 |
13 | 10b3aa0670 |
14 | 794723124 |
15 | 46330d23c |
hex | 2a251eecc |
11313213132 has 48 divisors (see below), whose sum is σ = 28586960640. Its totient is φ = 3461533248.
The previous prime is 11313213127. The next prime is 11313213133. The reversal of 11313213132 is 23131231311.
It is a happy number.
11313213132 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a nude number because it is divisible by every one of its digits.
It is a junction number, because it is equal to n+sod(n) for n = 11313213099 and 11313213108.
It is not an unprimeable number, because it can be changed into a prime (11313213133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 174648 + ... + 230495.
It is an arithmetic number, because the mean of its divisors is an integer number (595561680).
Almost surely, 211313213132 is an apocalyptic number.
11313213132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
11313213132 is an abundant number, since it is smaller than the sum of its proper divisors (17273747508).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11313213132 is a wasteful number, since it uses less digits than its factorization.
11313213132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 405342 (or 405340 counting only the distinct ones).
The product of its digits is 324, while the sum is 21.
Adding to 11313213132 its reverse (23131231311), we get a palindrome (34444444443).
The spelling of 11313213132 in words is "eleven billion, three hundred thirteen million, two hundred thirteen thousand, one hundred thirty-two".
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