1131344311300 has 72 divisors (see below), whose sum is σ = 2927722363776. Its totient is φ = 371024712960.

The previous prime is 1131344311297. The next prime is 1131344311313. The reversal of 1131344311300 is 31134431311.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 35118817 + ... + 35151016.

It is an arithmetic number, because the mean of its divisors is an integer number (40662810608).

Almost surely, 2^{1131344311300} is an apocalyptic number.

1131344311300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1131344311300 is an abundant number, since it is smaller than the sum of its proper divisors (1796378052476).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1131344311300 is a wasteful number, since it uses less digits than its factorization.

1131344311300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 70269877 (or 70269870 counting only the distinct ones).

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1131344311300 its reverse (31134431311), we get a palindrome (1162478742611).

The spelling of 1131344311300 in words is "one trillion, one hundred thirty-one billion, three hundred forty-four million, three hundred eleven thousand, three hundred".