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1132101031310 = 25234922178397
BaseRepresentation
bin10000011110010110011…
…110101101010110001110
311000020011001211010020022
4100132112132231112032
5122022020331000220
62224025142022142
7144535342664054
oct20362636552616
94006131733208
101132101031310
113a7137577a37
121634aa417952
13829ab52c762
143cb1898a1d4
151e6adc97925
hex107967ad58e

1132101031310 has 16 divisors (see below), whose sum is σ = 2126381067936. Its totient is φ = 433151698848.

The previous prime is 1132101031309. The next prime is 1132101031319. The reversal of 1132101031310 is 131301012311.

It is a super-2 number, since 2×11321010313102 (a number of 25 digits) contains 22 as substring.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1132101031319) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2461088969 + ... + 2461089428.

It is an arithmetic number, because the mean of its divisors is an integer number (132898816746).

Almost surely, 21132101031310 is an apocalyptic number.

1132101031310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1132101031310 is a deficient number, since it is larger than the sum of its proper divisors (994280036626).

1132101031310 is a wasteful number, since it uses less digits than its factorization.

1132101031310 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4922178427.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1132101031310 its reverse (131301012311), we get a palindrome (1263402043621).

The spelling of 1132101031310 in words is "one trillion, one hundred thirty-two billion, one hundred one million, thirty-one thousand, three hundred ten".

Divisors: 1 2 5 10 23 46 115 230 4922178397 9844356794 24610891985 49221783970 113210103131 226420206262 566050515655 1132101031310