Base | Representation |
---|---|
bin | 1010010011100011101111… |
… | …1111100000111000000000 |
3 | 1111010020121221121100200221 |
4 | 2210320323333200320000 |
5 | 2441122123314413240 |
6 | 40033241021352424 |
7 | 2246434653544543 |
oct | 244707377407000 |
9 | 44106557540627 |
10 | 11331130232320 |
11 | 3679561683538 |
12 | 1330070708714 |
13 | 6426a0822372 |
14 | 2b2602c9085a |
15 | 149b36ceaa4a |
hex | a4e3bfe0e00 |
11331130232320 has 80 divisors (see below), whose sum is σ = 27169463775168. Its totient is φ = 4532233789440.
The previous prime is 11331130232309. The next prime is 11331130232321. The reversal of 11331130232320 is 2323203113311.
It is a tau number, because it is divible by the number of its divisors (80).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11331130232321) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 59581222 + ... + 59771098.
Almost surely, 211331130232320 is an apocalyptic number.
11331130232320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11331130232320 is an abundant number, since it is smaller than the sum of its proper divisors (15838333542848).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11331130232320 is an equidigital number, since it uses as much as digits as its factorization.
11331130232320 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 213211 (or 213195 counting only the distinct ones).
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 11331130232320 its reverse (2323203113311), we get a palindrome (13654333345631).
The spelling of 11331130232320 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty million, two hundred thirty-two thousand, three hundred twenty".
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