Base | Representation |
---|---|
bin | 1010010011100011110000… |
… | …0011101010011100111000 |
3 | 1111010020122000122121212211 |
4 | 2210320330003222130320 |
5 | 2441122124104220440 |
6 | 40033241100544504 |
7 | 2246434666025143 |
oct | 244707403523470 |
9 | 44106560577784 |
10 | 11331131320120 |
11 | 3679562256847 |
12 | 1330070b52134 |
13 | 6426a0b13531 |
14 | 2b260309505a |
15 | 149b36e62eea |
hex | a4e3c0ea738 |
11331131320120 has 64 divisors (see below), whose sum is σ = 25558576081920. Its totient is φ = 4521167274624.
The previous prime is 11331131320037. The next prime is 11331131320139. The reversal of 11331131320120 is 2102313113311.
It is a junction number, because it is equal to n+sod(n) for n = 11331131320091 and 11331131320100.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 40159777 + ... + 40440943.
It is an arithmetic number, because the mean of its divisors is an integer number (399352751280).
Almost surely, 211331131320120 is an apocalyptic number.
11331131320120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11331131320120 is an abundant number, since it is smaller than the sum of its proper divisors (14227444761800).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11331131320120 is a wasteful number, since it uses less digits than its factorization.
11331131320120 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 283684 (or 283680 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 11331131320120 its reverse (2102313113311), we get a palindrome (13433444433431).
The spelling of 11331131320120 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-one million, three hundred twenty thousand, one hundred twenty".
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