Base | Representation |
---|---|
bin | 110100110100100100… |
… | …0111111011000011100 |
3 | 101211210100102020121122 |
4 | 1221221020333120130 |
5 | 3324302334123030 |
6 | 124035505150112 |
7 | 11123656363403 |
oct | 1515110773034 |
9 | 354710366548 |
10 | 113433114140 |
11 | 4411a043625 |
12 | 19b9862b338 |
13 | a9098482a8 |
14 | 56c113063a |
15 | 2e3d6e18e5 |
hex | 1a6923f61c |
113433114140 has 48 divisors (see below), whose sum is σ = 240914235744. Its totient is φ = 44859360000.
The previous prime is 113433114139. The next prime is 113433114143. The reversal of 113433114140 is 41411334311.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113433114143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1375967 + ... + 1456073.
It is an arithmetic number, because the mean of its divisors is an integer number (5019046578).
Almost surely, 2113433114140 is an apocalyptic number.
113433114140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
113433114140 is an abundant number, since it is smaller than the sum of its proper divisors (127481121604).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113433114140 is a wasteful number, since it uses less digits than its factorization.
113433114140 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 80918 (or 80916 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 26.
Adding to 113433114140 its reverse (41411334311), we get a palindrome (154844448451).
The spelling of 113433114140 in words is "one hundred thirteen billion, four hundred thirty-three million, one hundred fourteen thousand, one hundred forty".
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