Base | Representation |
---|---|
bin | 110100110100100110… |
… | …0110101000011010000 |
3 | 101211210102022100221112 |
4 | 1221221030311003100 |
5 | 3324303113323100 |
6 | 124035542512452 |
7 | 11124001054166 |
oct | 1515114650320 |
9 | 354712270845 |
10 | 113434120400 |
11 | 4411a670647 |
12 | 19b98a35728 |
13 | a909b0b303 |
14 | 56c1313236 |
15 | 2e3d83eb35 |
hex | 1a693350d0 |
113434120400 has 60 divisors (see below), whose sum is σ = 278863318272. Its totient is φ = 44318440320.
The previous prime is 113434120399. The next prime is 113434120421. The reversal of 113434120400 is 4021434311.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3280304 + ... + 3314703.
Almost surely, 2113434120400 is an apocalyptic number.
113434120400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
113434120400 is an abundant number, since it is smaller than the sum of its proper divisors (165429197872).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113434120400 is a wasteful number, since it uses less digits than its factorization.
113434120400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6595068 (or 6595057 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 113434120400 its reverse (4021434311), we get a palindrome (117455554711).
The spelling of 113434120400 in words is "one hundred thirteen billion, four hundred thirty-four million, one hundred twenty thousand, four hundred".
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