Base | Representation |
---|---|
bin | 11001110100011010000010… |
… | …010011011011110011100000 |
3 | 112220001111221011022200120000 |
4 | 121310122002103123303200 |
5 | 104340421041031114402 |
6 | 1041301151323020000 |
7 | 32626620405210243 |
oct | 3164320223336340 |
9 | 486044834280500 |
10 | 113552531504352 |
11 | 331aa3a37a9076 |
12 | 1089b2a906a600 |
13 | 4b48c5b2cbbc5 |
14 | 2007d86a7d25a |
15 | d1db667cec1c |
hex | 6746824dbce0 |
113552531504352 has 60 divisors (see below), whose sum is σ = 333954840924936. Its totient is φ = 37850843833920.
The previous prime is 113552531504351. The next prime is 113552531504353. The reversal of 113552531504352 is 253405135255311.
113552531504352 is a `hidden beast` number, since 1 + 1 + 3 + 5 + 525 + 31 + 5 + 0 + 43 + 52 = 666.
It is an interprime number because it is at equal distance from previous prime (113552531504351) and next prime (113552531504353).
It is a super-2 number, since 2×1135525315043522 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 113552531504298 and 113552531504307.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113552531504351) by changing a digit.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 21904420924 + ... + 21904426107.
Almost surely, 2113552531504352 is an apocalyptic number.
113552531504352 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
113552531504352 is an abundant number, since it is smaller than the sum of its proper divisors (220402309420584).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113552531504352 is an equidigital number, since it uses as much as digits as its factorization.
113552531504352 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43808847053 (or 43808847036 counting only the distinct ones).
The product of its (nonzero) digits is 1350000, while the sum is 45.
Adding to 113552531504352 its reverse (253405135255311), we get a palindrome (366957666759663).
The spelling of 113552531504352 in words is "one hundred thirteen trillion, five hundred fifty-two billion, five hundred thirty-one million, five hundred four thousand, three hundred fifty-two".
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