Base | Representation |
---|---|
bin | 1010011000010010011100… |
… | …0010111000001101110000 |
3 | 1111102000100121100100001111 |
4 | 2212010213002320031300 |
5 | 2443440030042441230 |
6 | 40134435414043104 |
7 | 2255342331253066 |
oct | 246044702701560 |
9 | 44360317310044 |
10 | 11412383171440 |
11 | 36aaa67864299 |
12 | 1343968049494 |
13 | 64a24c3c5774 |
14 | 2b65101ba036 |
15 | 14bce02b092a |
hex | a61270b8370 |
11412383171440 has 20 divisors (see below), whose sum is σ = 26533790873784. Its totient is φ = 4564953268544.
The previous prime is 11412383171411. The next prime is 11412383171489. The reversal of 11412383171440 is 4417138321411.
It is a happy number.
It is a tau number, because it is divible by the number of its divisors (20).
It is a Harshad number since it is a multiple of its sum of digits (40).
It is a junction number, because it is equal to n+sod(n) for n = 11412383171393 and 11412383171402.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 71327394742 + ... + 71327394901.
Almost surely, 211412383171440 is an apocalyptic number.
11412383171440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11412383171440 is an abundant number, since it is smaller than the sum of its proper divisors (15121407702344).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11412383171440 is a wasteful number, since it uses less digits than its factorization.
11412383171440 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 142654789656 (or 142654789650 counting only the distinct ones).
The product of its (nonzero) digits is 64512, while the sum is 40.
The spelling of 11412383171440 in words is "eleven trillion, four hundred twelve billion, three hundred eighty-three million, one hundred seventy-one thousand, four hundred forty".
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