Base | Representation |
---|---|
bin | 101011101011… |
… | …101111000010 |
3 | 210112210021100 |
4 | 223223233002 |
5 | 10412420310 |
6 | 1045235230 |
7 | 166222542 |
oct | 53535702 |
9 | 23483240 |
10 | 11451330 |
11 | 6511610 |
12 | 3a02b16 |
13 | 24ac347 |
14 | 1741322 |
15 | 1012ec0 |
hex | aebbc2 |
11451330 has 96 divisors (see below), whose sum is σ = 33359040. Its totient is φ = 2701440.
The previous prime is 11451313. The next prime is 11451337. The reversal of 11451330 is 3315411.
It is a super-2 number, since 2×114513302 = 262265917537800, which contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (11451337) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 42436 + ... + 42704.
It is an arithmetic number, because the mean of its divisors is an integer number (347490).
Almost surely, 211451330 is an apocalyptic number.
11451330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 11451330, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16679520).
11451330 is an abundant number, since it is smaller than the sum of its proper divisors (21907710).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11451330 is a wasteful number, since it uses less digits than its factorization.
11451330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 336 (or 333 counting only the distinct ones).
The product of its (nonzero) digits is 180, while the sum is 18.
The square root of 11451330 is about 3383.9813829275. The cubic root of 11451330 is about 225.3989957406.
Adding to 11451330 its reverse (3315411), we get a palindrome (14766741).
It can be divided in two parts, 11451 and 330, that added together give a triangular number (11781 = T153).
The spelling of 11451330 in words is "eleven million, four hundred fifty-one thousand, three hundred thirty".
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