Base | Representation |
---|---|
bin | 1010011110001011010000… |
… | …1011000001101000000000 |
3 | 1111202200110001121212101022 |
4 | 2213202310023001220000 |
5 | 3002114204444024100 |
6 | 40253124531525012 |
7 | 2265553063651364 |
oct | 247426413015000 |
9 | 44680401555338 |
10 | 11513535142400 |
11 | 3739954481205 |
12 | 135b497759768 |
13 | 65694c781415 |
14 | 2bb3882272a4 |
15 | 14e7606e9e85 |
hex | a78b42c1a00 |
11513535142400 has 60 divisors (see below), whose sum is σ = 28525682841942. Its totient is φ = 4605414051840.
The previous prime is 11513535142391. The next prime is 11513535142441. The reversal of 11513535142400 is 424153531511.
It is a happy number.
It can be written as a sum of positive squares in 3 ways, for example, as 4602020333824 + 6911514808576 = 2145232^2 + 2628976^2 .
It is a super-2 number, since 2×115135351424002 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 449734667 + ... + 449760266.
Almost surely, 211513535142400 is an apocalyptic number.
11513535142400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11513535142400 is an abundant number, since it is smaller than the sum of its proper divisors (17012147699542).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11513535142400 is an frugal number, since it uses more digits than its factorization.
11513535142400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 899494961 (or 899494940 counting only the distinct ones).
The product of its (nonzero) digits is 36000, while the sum is 35.
Adding to 11513535142400 its reverse (424153531511), we get a palindrome (11937688673911).
The spelling of 11513535142400 in words is "eleven trillion, five hundred thirteen billion, five hundred thirty-five million, one hundred forty-two thousand, four hundred".
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