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11523134332015 = 51727974487427
BaseRepresentation
bin1010011110101111000001…
…0101000001110001101111
31111210121020001012020000121
42213223300111001301233
53002243334342111030
640301353235505411
72266343003505055
oct247536025016157
944717201166017
1011523134332015
113742a2aa17469
121361316458267
1365781c405487
142bba190541d5
1514eb232d447a
hexa7af0541c6f

11523134332015 has 12 divisors (see below), whose sum is σ = 14689005842376. Its totient is φ = 8676242319488.

The previous prime is 11523134332007. The next prime is 11523134332043. The reversal of 11523134332015 is 51023343132511.

It is not a de Polignac number, because 11523134332015 - 23 = 11523134332007 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3987242269 + ... + 3987245158.

It is an arithmetic number, because the mean of its divisors is an integer number (1224083820198).

Almost surely, 211523134332015 is an apocalyptic number.

11523134332015 is a deficient number, since it is larger than the sum of its proper divisors (3165871510361).

11523134332015 is an equidigital number, since it uses as much as digits as its factorization.

11523134332015 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7974487466 (or 7974487449 counting only the distinct ones).

The product of its (nonzero) digits is 32400, while the sum is 34.

Adding to 11523134332015 its reverse (51023343132511), we get a palindrome (62546477464526).

The spelling of 11523134332015 in words is "eleven trillion, five hundred twenty-three billion, one hundred thirty-four million, three hundred thirty-two thousand, fifteen".

Divisors: 1 5 17 85 289 1445 7974487427 39872437135 135566286259 677831431295 2304626866403 11523134332015