Base | Representation |
---|---|
bin | 1010011110110111111101… |
… | …0111100001111101110000 |
3 | 1111210211102021211121000122 |
4 | 2213231333113201331300 |
5 | 3002313243214130112 |
6 | 40302431323505412 |
7 | 2266456323450536 |
oct | 247557727417560 |
9 | 44724367747018 |
10 | 11525534130032 |
11 | 3743a5160120a |
12 | 1361886088268 |
13 | 657b126501c0 |
14 | 2bbba5a60156 |
15 | 14ec13d1a872 |
hex | a7b7f5e1f70 |
11525534130032 has 20 divisors (see below), whose sum is σ = 24048470252520. Its totient is φ = 5319477290688.
The previous prime is 11525534130023. The next prime is 11525534130109. The reversal of 11525534130032 is 23003143552511.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 11525534129974 and 11525534130001.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27705610682 + ... + 27705611097.
It is an arithmetic number, because the mean of its divisors is an integer number (1202423512626).
Almost surely, 211525534130032 is an apocalyptic number.
It is an amenable number.
11525534130032 is an abundant number, since it is smaller than the sum of its proper divisors (12522936122488).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11525534130032 is a wasteful number, since it uses less digits than its factorization.
11525534130032 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55411221800 (or 55411221794 counting only the distinct ones).
The product of its (nonzero) digits is 54000, while the sum is 35.
Adding to 11525534130032 its reverse (23003143552511), we get a palindrome (34528677682543).
The spelling of 11525534130032 in words is "eleven trillion, five hundred twenty-five billion, five hundred thirty-four million, one hundred thirty thousand, thirty-two".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •