Base | Representation |
---|---|
bin | 11010001101111110110011… |
… | …101010110111001001110010 |
3 | 120010021112021020220022211002 |
4 | 122031332303222313021302 |
5 | 110103214340321301310 |
6 | 1045124403333122002 |
7 | 33200605220354030 |
oct | 3215766352671162 |
9 | 503245236808732 |
10 | 115310001353330 |
11 | 33817773702813 |
12 | 10b23a26189302 |
13 | 4c458c0236774 |
14 | 2069068c21550 |
15 | d4e72766bda5 |
hex | 68dfb3ab7272 |
115310001353330 has 128 divisors (see below), whose sum is σ = 249083033665536. Its totient is φ = 37578245760000.
The previous prime is 115310001353303. The next prime is 115310001353347. The reversal of 115310001353330 is 33353100013511.
It is a junction number, because it is equal to n+sod(n) for n = 115310001353293 and 115310001353302.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 174650135 + ... + 175309125.
It is an arithmetic number, because the mean of its divisors is an integer number (1945961200512).
Almost surely, 2115310001353330 is an apocalyptic number.
115310001353330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
115310001353330 is an abundant number, since it is smaller than the sum of its proper divisors (133773032312206).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
115310001353330 is a wasteful number, since it uses less digits than its factorization.
115310001353330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 659712.
The product of its (nonzero) digits is 6075, while the sum is 29.
Adding to 115310001353330 its reverse (33353100013511), we get a palindrome (148663101366841).
The spelling of 115310001353330 in words is "one hundred fifteen trillion, three hundred ten billion, one million, three hundred fifty-three thousand, three hundred thirty".
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