Base | Representation |
---|---|
bin | 1010011111101110000011… |
… | …0110111000010111100100 |
3 | 1111212012220020201221011211 |
4 | 2213323200312320113210 |
5 | 3003033012441440400 |
6 | 40313232232441204 |
7 | 2300512211655250 |
oct | 247734066702744 |
9 | 44765806657154 |
10 | 11540054640100 |
11 | 374a122aa5358 |
12 | 1364658b49204 |
13 | 6592b7a457ac |
14 | 2bc78230b260 |
15 | 1502b39b8dba |
hex | a7ee0db85e4 |
11540054640100 has 72 divisors (see below), whose sum is σ = 29542539934208. Its totient is φ = 3828958214400.
The previous prime is 11540054639977. The next prime is 11540054640133. The reversal of 11540054640100 is 104645004511.
It is a super-2 number, since 2×115400546401002 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 265878177 + ... + 265921576.
Almost surely, 211540054640100 is an apocalyptic number.
11540054640100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11540054640100 is an abundant number, since it is smaller than the sum of its proper divisors (18002485294108).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11540054640100 is a wasteful number, since it uses less digits than its factorization.
11540054640100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 531799805 (or 531799798 counting only the distinct ones).
The product of its (nonzero) digits is 9600, while the sum is 31.
Adding to 11540054640100 its reverse (104645004511), we get a palindrome (11644699644611).
The spelling of 11540054640100 in words is "eleven trillion, five hundred forty billion, fifty-four million, six hundred forty thousand, one hundred".
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