Base | Representation |
---|---|
bin | 1010100000100101110001… |
… | …1010101001000100110100 |
3 | 1111220122111200121122212011 |
4 | 2220021130122221010310 |
5 | 3003304131200422400 |
6 | 40324144403534004 |
7 | 2301551660543326 |
oct | 250113432510464 |
9 | 44818450548764 |
10 | 11555012514100 |
11 | 37554a93644a0 |
12 | 136753238a304 |
13 | 65a82c932403 |
14 | 2bd3a0ac7616 |
15 | 15088bc5b8ba |
hex | a825c6a9134 |
11555012514100 has 72 divisors (see below), whose sum is σ = 27354410830656. Its totient is φ = 4201739040000.
The previous prime is 11555012514029. The next prime is 11555012514103. The reversal of 11555012514100 is 141521055511.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11555012514103) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 91942305 + ... + 92067895.
It is an arithmetic number, because the mean of its divisors is an integer number (379922372648).
Almost surely, 211555012514100 is an apocalyptic number.
11555012514100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11555012514100 is an abundant number, since it is smaller than the sum of its proper divisors (15799398316556).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11555012514100 is a wasteful number, since it uses less digits than its factorization.
11555012514100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 209257 (or 209250 counting only the distinct ones).
The product of its (nonzero) digits is 5000, while the sum is 31.
Adding to 11555012514100 its reverse (141521055511), we get a palindrome (11696533569611).
The spelling of 11555012514100 in words is "eleven trillion, five hundred fifty-five billion, twelve million, five hundred fourteen thousand, one hundred".
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