Base | Representation |
---|---|
bin | 110110100010001100… |
… | …1000010011110001101 |
3 | 102012021201000012111010 |
4 | 1231010121002132031 |
5 | 3404321023001110 |
6 | 125444510315433 |
7 | 11314063410111 |
oct | 1550431023615 |
9 | 365251005433 |
10 | 117111531405 |
11 | 457374519a0 |
12 | 1a8444b8b79 |
13 | b07495325b |
14 | 594d893741 |
15 | 30a65e3020 |
hex | 1b4464278d |
117111531405 has 32 divisors (see below), whose sum is σ = 204435105408. Its totient is φ = 56775168000.
The previous prime is 117111531403. The next prime is 117111531437. The reversal of 117111531405 is 504135111711.
It is a happy number.
It is not a de Polignac number, because 117111531405 - 21 = 117111531403 is a prime.
It is a super-2 number, since 2×1171115314052 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (117111531403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1725105 + ... + 1791705.
It is an arithmetic number, because the mean of its divisors is an integer number (6388597044).
Almost surely, 2117111531405 is an apocalyptic number.
117111531405 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
117111531405 is a deficient number, since it is larger than the sum of its proper divisors (87323574003).
117111531405 is a wasteful number, since it uses less digits than its factorization.
117111531405 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 77277.
The product of its (nonzero) digits is 2100, while the sum is 30.
The spelling of 117111531405 in words is "one hundred seventeen billion, one hundred eleven million, five hundred thirty-one thousand, four hundred five".
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