Base | Representation |
---|---|
bin | 10101110110111011… |
… | …01001101101011101 |
3 | 1010021211120011011120 |
4 | 22323131221231131 |
5 | 143013133001010 |
6 | 5220242441153 |
7 | 563543153013 |
oct | 127335515535 |
9 | 33254504146 |
10 | 11735047005 |
11 | 4a82145560 |
12 | 23360631b9 |
13 | 11502b7cc6 |
14 | 7d476c8b3 |
15 | 48a385e70 |
hex | 2bb769b5d |
11735047005 has 64 divisors (see below), whose sum is σ = 21398335488. Its totient is φ = 5436034560.
The previous prime is 11735047001. The next prime is 11735047033. The reversal of 11735047005 is 50074053711.
It is not a de Polignac number, because 11735047005 - 22 = 11735047001 is a prime.
It is a super-2 number, since 2×117350470052 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11735047001) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 5490297 + ... + 5492433.
It is an arithmetic number, because the mean of its divisors is an integer number (334348992).
Almost surely, 211735047005 is an apocalyptic number.
11735047005 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
11735047005 is a deficient number, since it is larger than the sum of its proper divisors (9663288483).
11735047005 is a wasteful number, since it uses less digits than its factorization.
11735047005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3626.
The product of its (nonzero) digits is 14700, while the sum is 33.
The spelling of 11735047005 in words is "eleven billion, seven hundred thirty-five million, forty-seven thousand, five".
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