11937315962880 has 5760 divisors, whose sum is σ = 61966433894400. Its totient is φ = 2140353331200.

The previous prime is 11937315962879. The next prime is 11937315962909. The reversal of 11937315962880 is 8826951373911.

11937315962880 is a `hidden beast` number, since 1 + 1 + 9 + 3 + 7 + 31 + 596 + 2 + 8 + 8 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (5760).

It is a super-4 number, since 4×11937315962880⁴ (a number of 53 digits) contains 4444 as substring.

It is a Harshad number since it is a multiple of its sum of digits (63).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 383 ways as a sum of consecutive naturals, for example, 385074708465 + ... + 385074708495.

It is an arithmetic number, because the mean of its divisors is an integer number (10758061440).

Almost surely, 2^{11937315962880} is an apocalyptic number.

11937315962880 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11937315962880, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (30983216947200).

11937315962880 is an abundant number, since it is smaller than the sum of its proper divisors (50029117931520).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11937315962880 is a wasteful number, since it uses less digits than its factorization.

11937315962880 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 134 (or 95 counting only the distinct ones).

The product of its (nonzero) digits is 19595520, while the sum is 63.

The spelling of 11937315962880 in words is "eleven trillion, nine hundred thirty-seven billion, three hundred fifteen million, nine hundred sixty-two thousand, eight hundred eighty".