Base | Representation |
---|---|
bin | 10110010111001001… |
… | …01000001010100100 |
3 | 1010222200002222212100 |
4 | 23023210220022210 |
5 | 144041324424030 |
6 | 5303135252100 |
7 | 603334314054 |
oct | 131344501244 |
9 | 33880088770 |
10 | 12005311140 |
11 | 5100759a49 |
12 | 23b067a030 |
13 | 11942a4104 |
14 | 81c601564 |
15 | 4a3e6e360 |
hex | 2cb9282a4 |
12005311140 has 72 divisors (see below), whose sum is σ = 36519465528. Its totient is φ = 3192330240.
The previous prime is 12005311117. The next prime is 12005311259. The reversal of 12005311140 is 4111350021.
12005311140 is a `hidden beast` number, since 1 + 20 + 0 + 531 + 114 + 0 = 666.
It can be written as a sum of positive squares in 4 ways, for example, as 2815788096 + 9189523044 = 53064^2 + 95862^2 .
It is a Harshad number since it is a multiple of its sum of digits (18).
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 30931 + ... + 158010.
It is an arithmetic number, because the mean of its divisors is an integer number (507214799).
Almost surely, 212005311140 is an apocalyptic number.
12005311140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 12005311140, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18259732764).
12005311140 is an abundant number, since it is smaller than the sum of its proper divisors (24514154388).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12005311140 is a wasteful number, since it uses less digits than its factorization.
12005311140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 189309 (or 189304 counting only the distinct ones).
The product of its (nonzero) digits is 120, while the sum is 18.
Adding to 12005311140 its reverse (4111350021), we get a palindrome (16116661161).
The spelling of 12005311140 in words is "twelve billion, five million, three hundred eleven thousand, one hundred forty".
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