Base | Representation |
---|---|
bin | 11011010011011100110101… |
… | …100001011111100111001110 |
3 | 120202011220111122222112110001 |
4 | 123103130311201133213032 |
5 | 111214423300440222200 |
6 | 1103221435444434514 |
7 | 34202526463424416 |
oct | 3323346541374716 |
9 | 522156448875401 |
10 | 120083888601550 |
11 | 35298322598185 |
12 | 1157508b3a8a3a |
13 | 5200b2907b443 |
14 | 219213c441646 |
15 | dd39ce1e276a |
hex | 6d373585f9ce |
120083888601550 has 24 divisors (see below), whose sum is σ = 233067164661936. Its totient is φ = 45945139986240.
The previous prime is 120083888601529. The next prime is 120083888601553. The reversal of 120083888601550 is 55106888380021.
It is a junction number, because it is equal to n+sod(n) for n = 120083888601491 and 120083888601500.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120083888601553) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 52210385199 + ... + 52210387498.
It is an arithmetic number, because the mean of its divisors is an integer number (9711131860914).
Almost surely, 2120083888601550 is an apocalyptic number.
120083888601550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
120083888601550 is a deficient number, since it is larger than the sum of its proper divisors (112983276060386).
120083888601550 is a wasteful number, since it uses less digits than its factorization.
120083888601550 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 104420772732 (or 104420772727 counting only the distinct ones).
The product of its (nonzero) digits is 3686400, while the sum is 55.
The spelling of 120083888601550 in words is "one hundred twenty trillion, eighty-three billion, eight hundred eighty-eight million, six hundred one thousand, five hundred fifty".
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