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12012000000 = 2835671113
BaseRepresentation
bin10110010111111100…
…01001001100000000
31011000010200211020220
423023332021030000
5144100033000000
65303534503040
7603445213110
oct131376111400
934003624226
1012012000000
115104508430
1223b2964a80
1311957a6810
1481d463040
154a48411a0
hex2cbf89300

12012000000 has 1008 divisors, whose sum is σ = 53654313216. Its totient is φ = 2304000000.

The previous prime is 12011999983. The next prime is 12012000031. The reversal of 12012000000 is 21021.

It is a happy number.

It is a Harshad number since it is a multiple of its sum of digits (6).

It is a super Niven number, because it is divisible the sum of any subset of its (nonzero) digits.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 111 ways as a sum of consecutive naturals, for example, 923999994 + ... + 924000006.

Almost surely, 212012000000 is an apocalyptic number.

12012000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12012000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (26827156608).

12012000000 is an abundant number, since it is smaller than the sum of its proper divisors (41642313216).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12012000000 is an frugal number, since it uses more digits than its factorization.

12012000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 80 (or 41 counting only the distinct ones).

The product of its (nonzero) digits is 4, while the sum is 6.

Adding to 12012000000 its reverse (21021), we get a palindrome (12012021021).

The spelling of 12012000000 in words is "twelve billion, twelve million", and thus it is an aban number and an uban number.