Base | Representation |
---|---|
bin | 1010111011001100100110… |
… | …0111110101010011110000 |
3 | 1120112100100200110221001020 |
4 | 2232303021213311103300 |
5 | 3033301300433101000 |
6 | 41314142051335440 |
7 | 2346563212500441 |
oct | 256631147652360 |
9 | 46470320427036 |
10 | 12012111222000 |
11 | 39113426a218a |
12 | 142003b8b1580 |
13 | 6919778c6a36 |
14 | 2d75642ad2c8 |
15 | 15c6e1310ba0 |
hex | aecc99f54f0 |
12012111222000 has 80 divisors (see below), whose sum is σ = 38727046599072. Its totient is φ = 3203229657600.
The previous prime is 12012111221989. The next prime is 12012111222091. The reversal of 12012111222000 is 22211121021.
It is a tau number, because it is divible by the number of its divisors (80).
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1001003269 + ... + 1001015268.
Almost surely, 212012111222000 is an apocalyptic number.
12012111222000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
12012111222000 is an abundant number, since it is smaller than the sum of its proper divisors (26714935377072).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12012111222000 is a wasteful number, since it uses less digits than its factorization.
12012111222000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2002018563 (or 2002018547 counting only the distinct ones).
The product of its (nonzero) digits is 32, while the sum is 15.
Adding to 12012111222000 its reverse (22211121021), we get a palindrome (12034322343021).
The spelling of 12012111222000 in words is "twelve trillion, twelve billion, one hundred eleven million, two hundred twenty-two thousand".
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