Base | Representation |
---|---|
bin | 1010111011001100101000… |
… | …1110011001010100111000 |
3 | 1120112100101101111111222122 |
4 | 2232303022032121110320 |
5 | 3033301311030043000 |
6 | 41314143052140412 |
7 | 2346563364432650 |
oct | 256631216312470 |
9 | 46470341444878 |
10 | 12012121331000 |
11 | 391134837722a |
12 | 1420043167708 |
13 | 691979a260ab |
14 | 2d7565781360 |
15 | 15c6e215b085 |
hex | aecca399538 |
12012121331000 has 128 divisors (see below), whose sum is σ = 32603306112000. Its totient is φ = 4056972163200.
The previous prime is 12012121330997. The next prime is 12012121331017. The reversal of 12012121331000 is 13312121021.
12012121331000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×120121213310002 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 12012121331000.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 12337100 + ... + 13275099.
It is an arithmetic number, because the mean of its divisors is an integer number (254713329000).
Almost surely, 212012121331000 is an apocalyptic number.
12012121331000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
12012121331000 is an abundant number, since it is smaller than the sum of its proper divisors (20591184781000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12012121331000 is a wasteful number, since it uses less digits than its factorization.
12012121331000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25612294 (or 25612280 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 12012121331000 its reverse (13312121021), we get a palindrome (12025433452021).
The spelling of 12012121331000 in words is "twelve trillion, twelve billion, one hundred twenty-one million, three hundred thirty-one thousand".
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