Base | Representation |
---|---|
bin | 1010111011001101110010… |
… | …1100111000110100110110 |
3 | 1120112101011222210022001000 |
4 | 2232303130230320310312 |
5 | 3033302424404023410 |
6 | 41314233524144130 |
7 | 2346604150312104 |
oct | 256633454706466 |
9 | 46471158708030 |
10 | 12012431314230 |
11 | 391149734a216 |
12 | 142010ab38046 |
13 | 6919c900ac19 |
14 | 2d75949d2c74 |
15 | 15c70e48cdc0 |
hex | aecdcb38d36 |
12012431314230 has 128 divisors (see below), whose sum is σ = 33960167055360. Its totient is φ = 3016198892160.
The previous prime is 12012431314151. The next prime is 12012431314231. The reversal of 12012431314230 is 3241313421021.
12012431314230 is a `hidden beast` number, since 1 + 201 + 2 + 4 + 3 + 1 + 31 + 423 + 0 = 666.
It is a super-3 number, since 3×120124313142303 (a number of 40 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 12012431314194 and 12012431314203.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12012431314231) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 19084594 + ... + 19703973.
It is an arithmetic number, because the mean of its divisors is an integer number (265313805120).
Almost surely, 212012431314230 is an apocalyptic number.
12012431314230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12012431314230 is an abundant number, since it is smaller than the sum of its proper divisors (21947735741130).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12012431314230 is a wasteful number, since it uses less digits than its factorization.
12012431314230 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 38788651 (or 38788645 counting only the distinct ones).
The product of its (nonzero) digits is 3456, while the sum is 27.
Adding to 12012431314230 its reverse (3241313421021), we get a palindrome (15253744735251).
The spelling of 12012431314230 in words is "twelve trillion, twelve billion, four hundred thirty-one million, three hundred fourteen thousand, two hundred thirty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.091 sec. • engine limits •